-2/x-2+3/x+2=-15/x^2-4

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Solution for -2/x-2+3/x+2=-15/x^2-4 equation:


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x-2/x-2+2 = -15/(x^2)-4 // + -15/(x^2)-4

3/x-2/x-(-15/(x^2))-2+2+4 = 0

3/x-2/x+15*x^-2-2+2+4 = 0

x^-1+15*x^-2+4 = 0

t_1 = x^-1

15*t_1^2+1*t_1^1+4 = 0

15*t_1^2+t_1+4 = 0

DELTA = 1^2-(4*4*15)

DELTA = -239

DELTA < 0

x belongs to the empty set

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